C program for binary addition using two's complement

1 Pseudocode:

1.  Start
2.      Ask user to enter two 8-bit numbers: num1, num2
3.      carry = 0
4.      Begin Addition from LSB
5.      sum = num1[i] + num2[i] + carry
6.      If sum of two bits >= 2, carry = 1
7.      Otherwise, carry = 0
8.      sum = sum % 2
9.      Repeat 5 through 8 until all bits are added
10.  Display sum
11.  End

2 Program:

#include <stdio.h>

#include <conio.h>

#include <math.h>

void main(){

clrscr();

            int c = 0,numa[8]={0},numb[8]={0},sum[8]={0};

            printf("\tADDITION USING TWO'S COMPLEMENT");

            printf("\nEnter two 8-bit binary numbers\n");

            printf("\nEnter first number: ");

            for(int i = 0; i<8; i++){

                        scanf("%d",&numa[i]);

            }

            printf("\nEnter second number: ");

            for(i = 0; i<8; i++){

                        scanf("%d",&numb[i]);

            }

            for(i = 7; i >= 0; i--){

                        sum[i] = numa[i]+ numb[i] + c;

                        if(sum[i]>=2){

                                    c = 1;

                        }

                        else

                                    c = 0;

                        sum[i] = sum[i]%2;

            }

            printf("\nSum is: ");

            for(i = 0; i<8; i++){

                        printf("%d",sum[i]);

            }

getch();

}

©Dixit Bhatta 2013