/*Program for implementing Restoring
Division algorithm.*/
#include <stdio.h>
#include <conio.h>
#include <math.h>
int a=0,b=0,c=0,com[5]={1,0,0,0,0},s=0;
int anum[5]={0},anumcp[5] ={0},bnum[5]={0};
int acomp[5]={0},bcomp[5]={0},rem[5]={0},quo[5]={0},res[5]={0};
void binary(){
a = fabs(a);
b = fabs(b);
int r, r2, i, temp;
for(i = 0; i
< 5; i++){
r = a % 2;
a = a / 2;
r2 = b % 2;
b = b / 2;
anum[i] = r;
anumcp[i] = r;
bnum[i] = r2;
if(r2 == 0){
bcomp[i] = 1;
}
if(r == 0){
acomp[i] =1;
}
}
//part for two's complementing
c =
0;
for( i
= 0; i < 5; i++){
res[i] = com[i]+
bcomp[i] + c;
if(res[i]>=2){
c = 1;
}
else
c = 0;
res[i] = res[i]%2;
}
for(i
= 4; i>= 0; i--){
bcomp[i] = res[i];
}
}
void add(int num[]){
int i;
c = 0;
for( i = 0; i
< 5; i++){
res[i] = rem[i]+
num[i] + c;
if(res[i]>=2){
c = 1;
}
else
c = 0;
res[i] = res[i]%2;
}
for(i = 4; i>=
0; i--){
rem[i] = res[i];
printf("%d",rem[i]);
}
printf(":");
for(i = 4; i>=
0; i--){
printf("%d",anumcp[i]);
}
}
void shl(){//for shift left
int i;
for(i = 4; i
> 0 ; i--){//shift the remainder
rem[i] = rem[i-1];
}
rem[0] = anumcp[4];
for(i = 4; i
> 0 ; i--){//shift the remtient
anumcp[i] = anumcp[i-1];
}
anumcp[0] = 0;
printf("\nSHIFT
LEFT: ");//display together
for(i = 4; i>=
0; i--){
printf("%d",rem[i]);
}
printf(":");
for(i = 4; i>=
0; i--){
printf("%d",anumcp[i]);
}
}
void main(){
clrscr();
int i;
printf("\t\tRESTORING
DIVISION ALGORITHM");
printf("\nEnter
two numbers to multiply: ");
printf("\nBoth
must be less than 16");
//simulating for two
numbers each below 16
do{
printf("\nEnter
A: ");
scanf("%d",&a);
printf("Enter
B: ");
scanf("%d",&b);
}while(a>=16
|| b>=16);
printf("\nExpected
Quotient = %d", a/b);
printf("\nExpected
Remainder = %d", a%b);
if(a*b <0){
s = 1;
}
binary();
printf("\n\nUnsigned
Binary Equivalents are: ");
printf("\nA
= ");
for(i = 4; i>=
0; i--){
printf("%d",anum[i]);
}
printf("\nB
= ");
for(i = 4; i>=
0; i--){
printf("%d",bnum[i]);
}
printf("\nB'+
1 = ");
for(i = 4; i>=
0; i--){
printf("%d",bcomp[i]);
}
printf("\n\n-->");
//division part
shl();
for(i=0;i<5;i++){
printf("\n-->");
//start with subtraction
printf("\nSUB
B: ");
add(bcomp);
if(rem[4]==1){//simply add for restoring
printf("\n-->RESTORE");
printf("\nADD
B: ");
anumcp[0] = 0;
add(bnum);
}
else{
anumcp[0] = 1;
}
if(i<4)
shl();
}
printf("\n----------------------------");
printf("\nSign
of the result = %d",s);
printf("\nRemainder
is = ");
for(i = 4; i>=
0; i--){
printf("%d",rem[i]);
}
printf("\nQuotient
is = ");
for(i = 4; i>=
0; i--){
printf("%d",anumcp[i]);
}
getch();
}
hey bro can i get the explanation for this?.......
ReplyDeleteHi Sailesh,
DeleteI think you can get a good description of the algorithm in any book related with Computer Architecture. I would personally recommend "Computer System Architecture" by Morris Mano.
Regarding my program, the following algorithm should help:
1. Start
2. Quotient = 0, Remainder =0 and Sign = 0
3. Ask user to enter two decimal numbers: n1, n2
4. Convert their absolute values into binary and store in arrays num1 and num2
5. Two’s complement num2 and store as ncom
6. Create a copy of num1 as ncopy
7. If the product is negative, set sign = 1
8. Shift left Remainder : ncopy; counter = 0
9. Add ncom to Remainder
9.1 Set LSB of ncopy as 0.
9.2 If result is negative, restore the remainder
9.3 Otherwise, Set LSB of ncopy as 1.
10. If counter < bits in num1, Shift left Remainder : ncopy
11. counter = counter + 1
12. Repeat 9, 10 and 11 until all bits of num1 are traced
13. Display final result as Sign, Remainder : ncopy
14. End
28/-4 can you please show me using restoring division. I tried but not getting the answer.
DeleteWhy below 16?
ReplyDeletebecause the binary equivalent of 16 is 10000
ReplyDeleteand the limit of n is 4 bit
This comment has been removed by the author.
ReplyDeleteOutput ??
ReplyDeleteerror showing bro in conio.h
ReplyDeleteconio.h is supported in only turbo cpp. I modern coding ide such as coding blocks, jet brains, eclipse wont support conio hedder file.
Delete